Question
A and B are two stations 390 km apart. One train starts at
station A at 10 AM and travels towards B at 65 kmph. Another
train starts at B at 11 AM and travels towards A at 35 kmph..
At what time do they meet ??
Answer
Let's represent the time taken by the second train as t hours,
First train leaves one hour before so time taken by first train is t + 1 hours.
We know that distance = speed * time
So,
Distance traveled by first train at 65 kmph is 65 ( t + 1 )
Similarly distance covered by second train at 35 kmph is 35t hours.
Since they are moving towards each other, distance covered would be added up.
==>> 65 ( t + 1 ) + 35 t = 390 km
==>> 65t + 65 + 35t = 390
==>> 65t + 35t = 390 - 65
==>> 100 t = 325
==>> t = 3.25 hours
Meeting time is 11 am + 3.25 hours
==>> 11 am + 3 am = 2 am
==>> additional 0.25 hours
== 0.25 × 60 = 15 minutes
==>> additional 15 minutes
Hence both the train meet at 2.15 pm !!!
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