All of us have observed this . When we squeeze a balloon ,( having air inside it ) it pops . Why ?
It is according to " Boyle's Law " .
Boyle's law states that " pressure of the gas is inversly proportional to its volume at constant temperature . "
V1 / V2 = P2 / P1
Where V1 , P1 = initial volume and pressure
V2 , P2 = final volume and pressure
Thus , we can conclude that when we squeeze the balloon ( which is already having air inside it ) the volume of air decreases , it increases the pressure inside balloon and it pops out .
It is according to " Boyle's Law " .
Boyle's law states that " pressure of the gas is inversly proportional to its volume at constant temperature . "
V1 / V2 = P2 / P1
Where V1 , P1 = initial volume and pressure
V2 , P2 = final volume and pressure
Thus , we can conclude that when we squeeze the balloon ( which is already having air inside it ) the volume of air decreases , it increases the pressure inside balloon and it pops out .
