Question
A is 9 year older than B. In 10 years, A will be twice as old as B was 10 years ago.
What is the present age of A and B ??
Answer
Let the age of A is x.
Let the age of B is y.
At present, A is 9 year older than B
== >> x = y + 9
In 10 years, A age x + 10
In 10 years, B age y - 10
It is given that A will be twice the age of B who was 10 years ago.
==>> x + 10 = 2 ( y - 10 )
Now substitute x = y + 9
y + 9 + 10 = 2y - 20
y + 19 = 2y - 20
y = 39
Now substitute y in x = y + 9
x = 48
Hence,
Present age of A = x = 48
Present age of B = y = 39
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